6(2x^2)=81

Solution for 6(2x^2)=81 equation:

6(2x^2)=81

We move all terms to the left:

6(2x^2)-(81)=0

a = 62; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·62·(-81)
Δ = 20088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20088}=\sqrt{324*62}=\sqrt{324}*\sqrt{62}=18\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{62}}{2*62}=\frac{0-18\sqrt{62}}{124}
=-\frac{18\sqrt{62}}{124}
=-\frac{9\sqrt{62}}{62}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{62}}{2*62}=\frac{0+18\sqrt{62}}{124}
=\frac{18\sqrt{62}}{124}
=\frac{9\sqrt{62}}{62}
$